• TropicalDingdong@lemmy.world
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    1 year ago

    not saying there’s not a climate change disaster happening, but some of these analyses are a little misleading.

    Except that to only say “…since 1979” is to comment in either ignorance or bad faith (your pick). We maintained record breaking temps ALL above the prior record for 36 is the damn point, and to miss that is to miss the entire thing.

    There have been 44 years since 1979. Lets say the probability of getting 1 day above the 1979 record in a given year is 1/44 (uniform). The probability of even getting a week of the hottest days in one year would be (1/44)^7, would be a one in 300 billion chance. There are some issues and some assumptions I’m making for convenience, but its not ok to make idle comments with no comprehension of the scale of extremity this event represents.

    As in, do you have any fucking idea how unlikely that is? This isn’t an ‘oopsie poopsie’ funny record event.

    • bloodfoot@programming.dev
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      1 year ago

      Not to be too pedantic but your back of the envelope probabilities are based on inaccurate assumptions and probably several orders of magnitude off. Specifically, your not just assuming uniform but also independent from one day to the next. A more accurate treatment would be to assume conditional dependence from one day to the next (the Markov property). Once you have a record hot day, you are significantly more likely to have another record hot day following it.

      That said, it’s still low probability, just not as low as what you’re saying.

      • TropicalDingdong@lemmy.world
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        1 year ago

        Any thoughts on how I could incorporate that for a better back of the napkin?

        (Also, that number is only consider that the number presented was based on 7 independent events, not 34)

        • bloodfoot@programming.dev
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          1 year ago

          If we stick with your 1/44 assumption, we can then assume 50% chance that the following day will also be a record setting day (probably too low still but the math is easier). Your one week estimate would be (1/44)*(1/2)^6.